1342462040401 has 4 divisors (see below), whose sum is σ = 1343312239600. Its totient is φ = 1341611841204.

The previous prime is 1342462040399. The next prime is 1342462040411. The reversal of 1342462040401 is 1040402642431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342462040401 - 2¹ = 1342462040399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342462040411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425097231 + ... + 425100388.

It is an arithmetic number, because the mean of its divisors is an integer number (335828059900).

Almost surely, 2^{1342462040401} is an apocalyptic number.

It is an amenable number.

1342462040401 is a deficient number, since it is larger than the sum of its proper divisors (850199199).

1342462040401 is an equidigital number, since it uses as much as digits as its factorization.

1342462040401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 850199198.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 1342462040401 its reverse (1040402642431), we get a palindrome (2382864682832).

The spelling of 1342462040401 in words is "one trillion, three hundred forty-two billion, four hundred sixty-two million, forty thousand, four hundred one".