Base | Representation |
---|---|
bin | 1100001101011101010101… |
… | …0110011100111001100111 |
3 | 1202112110011212202202022021 |
4 | 3003113111112130321213 |
5 | 3224430110132420201 |
6 | 44315304403044011 |
7 | 2553643513050010 |
oct | 303272526347147 |
9 | 52473155682267 |
10 | 13425352232551 |
11 | 43067293786a6 |
12 | 1609b0b370607 |
13 | 76500b7b839c |
14 | 345b0d260007 |
15 | 184356b2cea1 |
hex | c35d559ce67 |
13425352232551 has 16 divisors (see below), whose sum is σ = 15366093652224. Its totient is φ = 11490325665984.
The previous prime is 13425352232491. The next prime is 13425352232587. The reversal of 13425352232551 is 15523225352431.
It is a cyclic number.
It is not a de Polignac number, because 13425352232551 - 213 = 13425352224359 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13425352232498 and 13425352232507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13425352233551) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25315851 + ... + 25840723.
It is an arithmetic number, because the mean of its divisors is an integer number (960380853264).
Almost surely, 213425352232551 is an apocalyptic number.
13425352232551 is a deficient number, since it is larger than the sum of its proper divisors (1940741419673).
13425352232551 is an equidigital number, since it uses as much as digits as its factorization.
13425352232551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 530310.
The product of its digits is 1080000, while the sum is 43.
Adding to 13425352232551 its reverse (15523225352431), we get a palindrome (28948577584982).
The spelling of 13425352232551 in words is "thirteen trillion, four hundred twenty-five billion, three hundred fifty-two million, two hundred thirty-two thousand, five hundred fifty-one".
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