Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1000011001000000010011 |
3 | 1202112110100212220011011110 |
4 | 3003113121220121000103 |
5 | 3224430232023402201 |
6 | 44315315450144403 |
7 | 2553645344326665 |
oct | 303273150310023 |
9 | 52473325804143 |
10 | 13425424044051 |
11 | 4306765966748 |
12 | 1609b2b422103 |
13 | 76502063c5b6 |
14 | 345b189d4535 |
15 | 18435d0b56d6 |
hex | c35d9a19013 |
13425424044051 has 4 divisors (see below), whose sum is σ = 17900565392072. Its totient is φ = 8950282696032.
The previous prime is 13425424044047. The next prime is 13425424044077. The reversal of 13425424044051 is 15044042452431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13425424044051 - 22 = 13425424044047 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13425424046051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237570674006 + ... + 2237570674011.
It is an arithmetic number, because the mean of its divisors is an integer number (4475141348018).
Almost surely, 213425424044051 is an apocalyptic number.
13425424044051 is a deficient number, since it is larger than the sum of its proper divisors (4475141348021).
13425424044051 is an equidigital number, since it uses as much as digits as its factorization.
13425424044051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4475141348020.
The product of its (nonzero) digits is 307200, while the sum is 39.
Adding to 13425424044051 its reverse (15044042452431), we get a palindrome (28469466496482).
The spelling of 13425424044051 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, forty-four thousand, fifty-one".
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