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13425424210153 is a prime number
BaseRepresentation
bin1100001101011101100110…
…1001000001100011101001
31202112110100220012121000101
43003113121221001203221
53224430232044211103
644315315453505401
72553645345621154
oct303273151014351
952473326177011
1013425424210153
114306765a6a51a
121609b2b4a2261
1376502069a097
14345b18a38c9b
1518435d0e9a1d
hexc35d9a418e9

13425424210153 has 2 divisors, whose sum is σ = 13425424210154. Its totient is φ = 13425424210152.

The previous prime is 13425424210069. The next prime is 13425424210171. The reversal of 13425424210153 is 35101242452431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11670231133584 + 1755193076569 = 3416172^2 + 1324837^2 .

It is an emirp because it is prime and its reverse (35101242452431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13425424210153 is a prime.

It is not a weakly prime, because it can be changed into another prime (13425424210183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712105076 + 6712712105077.

It is an arithmetic number, because the mean of its divisors is an integer number (6712712105077).

Almost surely, 213425424210153 is an apocalyptic number.

It is an amenable number.

13425424210153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425424210153 is an equidigital number, since it uses as much as digits as its factorization.

13425424210153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 13425424210153 its reverse (35101242452431), we get a palindrome (48526666662584).

The spelling of 13425424210153 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, two hundred ten thousand, one hundred fifty-three".