Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1001000001101010101011 |
3 | 1202112110100220012121122001 |
4 | 3003113121221001222223 |
5 | 3224430232044214403 |
6 | 44315315453511431 |
7 | 2553645345622366 |
oct | 303273151015253 |
9 | 52473326177561 |
10 | 13425424210603 |
11 | 4306765a6a899 |
12 | 1609b2b4a2577 |
13 | 76502069a352 |
14 | 345b18a390dd |
15 | 18435d0e9c1d |
hex | c35d9a41aab |
13425424210603 has 2 divisors, whose sum is σ = 13425424210604. Its totient is φ = 13425424210602.
The previous prime is 13425424210577. The next prime is 13425424210613. The reversal of 13425424210603 is 30601242452431.
13425424210603 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13425424210603 is a prime.
It is not a weakly prime, because it can be changed into another prime (13425424210613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712712105301 + 6712712105302.
It is an arithmetic number, because the mean of its divisors is an integer number (6712712105302).
Almost surely, 213425424210603 is an apocalyptic number.
13425424210603 is a deficient number, since it is larger than the sum of its proper divisors (1).
13425424210603 is an equidigital number, since it uses as much as digits as its factorization.
13425424210603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 138240, while the sum is 37.
The spelling of 13425424210603 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, two hundred ten thousand, six hundred three".
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