13425430143353 has 4 divisors (see below), whose sum is σ = 13425442103808. Its totient is φ = 13425418182900.

The previous prime is 13425430143271. The next prime is 13425430143457. The reversal of 13425430143353 is 35334103452431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13425430143353 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13425430143353.

It is not an unprimeable number, because it can be changed into a prime (13425430143953) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4099301 + ... + 6607202.

It is an arithmetic number, because the mean of its divisors is an integer number (3356360525952).

Almost surely, 2^{13425430143353} is an apocalyptic number.

It is an amenable number.

13425430143353 is a deficient number, since it is larger than the sum of its proper divisors (11960455).

13425430143353 is a wasteful number, since it uses less digits than its factorization.

13425430143353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11960454.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 13425430143353 its reverse (35334103452431), we get a palindrome (48759533595784).

The spelling of 13425430143353 in words is "thirteen trillion, four hundred twenty-five billion, four hundred thirty million, one hundred forty-three thousand, three hundred fifty-three".