Base | Representation |
---|---|
bin | 10011100010011011000… |
… | …000101000101100111011 |
3 | 11202100120020000202110021 |
4 | 103202123000220230323 |
5 | 133444201342302142 |
6 | 2504443525431311 |
7 | 166000430236666 |
oct | 23423300505473 |
9 | 4670506022407 |
10 | 1342630431547 |
11 | 4784519703a9 |
12 | 19826426b537 |
13 | 997c0116172 |
14 | 48dab23a6dd |
15 | 24dd17ee267 |
hex | 1389b028b3b |
1342630431547 has 2 divisors, whose sum is σ = 1342630431548. Its totient is φ = 1342630431546.
The previous prime is 1342630431533. The next prime is 1342630431553. The reversal of 1342630431547 is 7451340362431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1342630431547 - 211 = 1342630429499 is a prime.
It is not a weakly prime, because it can be changed into another prime (1342630471547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671315215773 + 671315215774.
It is an arithmetic number, because the mean of its divisors is an integer number (671315215774).
Almost surely, 21342630431547 is an apocalyptic number.
1342630431547 is a deficient number, since it is larger than the sum of its proper divisors (1).
1342630431547 is an equidigital number, since it uses as much as digits as its factorization.
1342630431547 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 725760, while the sum is 43.
Adding to 1342630431547 its reverse (7451340362431), we get a palindrome (8793970793978).
The spelling of 1342630431547 in words is "one trillion, three hundred forty-two billion, six hundred thirty million, four hundred thirty-one thousand, five hundred forty-seven".
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