Base | Representation |
---|---|
bin | 10011100010011011000… |
… | …000111010001011101010 |
3 | 11202100120020011101200002 |
4 | 103202123000322023222 |
5 | 133444201402100041 |
6 | 2504443531143002 |
7 | 166000430655512 |
oct | 23423300721352 |
9 | 4670506141602 |
10 | 1342630503146 |
11 | 478451a0a179 |
12 | 1982642a4a62 |
13 | 997c013c92a |
14 | 48dab258842 |
15 | 24dd181559b |
hex | 1389b03a2ea |
1342630503146 has 4 divisors (see below), whose sum is σ = 2013945754722. Its totient is φ = 671315251572.
The previous prime is 1342630503143. The next prime is 1342630503223. The reversal of 1342630503146 is 6413050362431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 971779952521 + 370850550625 = 985789^2 + 608975^2 .
It is a super-2 number, since 2×13426305031462 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1342630503143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335657625785 + ... + 335657625788.
Almost surely, 21342630503146 is an apocalyptic number.
1342630503146 is a deficient number, since it is larger than the sum of its proper divisors (671315251576).
1342630503146 is an equidigital number, since it uses as much as digits as its factorization.
1342630503146 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 671315251575.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 1342630503146 its reverse (6413050362431), we get a palindrome (7755680865577).
The spelling of 1342630503146 in words is "one trillion, three hundred forty-two billion, six hundred thirty million, five hundred three thousand, one hundred forty-six".
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