Search a number
-
+
1342630503146 = 2671315251573
BaseRepresentation
bin10011100010011011000…
…000111010001011101010
311202100120020011101200002
4103202123000322023222
5133444201402100041
62504443531143002
7166000430655512
oct23423300721352
94670506141602
101342630503146
11478451a0a179
121982642a4a62
13997c013c92a
1448dab258842
1524dd181559b
hex1389b03a2ea

1342630503146 has 4 divisors (see below), whose sum is σ = 2013945754722. Its totient is φ = 671315251572.

The previous prime is 1342630503143. The next prime is 1342630503223. The reversal of 1342630503146 is 6413050362431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 971779952521 + 370850550625 = 985789^2 + 608975^2 .

It is a super-2 number, since 2×13426305031462 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1342630503143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335657625785 + ... + 335657625788.

Almost surely, 21342630503146 is an apocalyptic number.

1342630503146 is a deficient number, since it is larger than the sum of its proper divisors (671315251576).

1342630503146 is an equidigital number, since it uses as much as digits as its factorization.

1342630503146 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671315251575.

The product of its (nonzero) digits is 155520, while the sum is 38.

Adding to 1342630503146 its reverse (6413050362431), we get a palindrome (7755680865577).

The spelling of 1342630503146 in words is "one trillion, three hundred forty-two billion, six hundred thirty million, five hundred three thousand, one hundred forty-six".

Divisors: 1 2 671315251573 1342630503146