Base | Representation |
---|---|
bin | 11001000000100110… |
… | …01100000011100001 |
3 | 1021122201220020222210 |
4 | 30200103030003201 |
5 | 204444230143123 |
6 | 10100154552333 |
7 | 653504640666 |
oct | 144023140341 |
9 | 37581806883 |
10 | 13426802913 |
11 | 5770097837 |
12 | 27287386a9 |
13 | 135c938cc4 |
14 | 915309a6d |
15 | 538b5be93 |
hex | 3204cc0e1 |
13426802913 has 4 divisors (see below), whose sum is σ = 17902403888. Its totient is φ = 8951201940.
The previous prime is 13426802891. The next prime is 13426802923. The reversal of 13426802913 is 31920862431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31920862431 = 3 ⋅10640287477.
It is not a de Polignac number, because 13426802913 - 26 = 13426802849 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13426802923) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2237800483 + ... + 2237800488.
It is an arithmetic number, because the mean of its divisors is an integer number (4475600972).
Almost surely, 213426802913 is an apocalyptic number.
It is an amenable number.
13426802913 is a deficient number, since it is larger than the sum of its proper divisors (4475600975).
13426802913 is an equidigital number, since it uses as much as digits as its factorization.
13426802913 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4475600974.
The product of its (nonzero) digits is 62208, while the sum is 39.
The spelling of 13426802913 in words is "thirteen billion, four hundred twenty-six million, eight hundred two thousand, nine hundred thirteen".
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