Base | Representation |
---|---|
bin | 1100001101101110110101… |
… | …0111000101101111011001 |
3 | 1202112220022021111002121121 |
4 | 3003123231113011233121 |
5 | 3230014220301122223 |
6 | 44321402501005241 |
7 | 2554201105432153 |
oct | 303335527055731 |
9 | 52486267432547 |
10 | 13430050020313 |
11 | 430871a130123 |
12 | 160aa006b3821 |
13 | 7655a9b53264 |
14 | 346037133ad3 |
15 | 18452e28a15d |
hex | c36ed5c5bd9 |
13430050020313 has 4 divisors (see below), whose sum is σ = 13450616713188. Its totient is φ = 13409483327440.
The previous prime is 13430050020287. The next prime is 13430050020349. The reversal of 13430050020313 is 31302005003431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2569650678169 + 10860399342144 = 1603013^2 + 3295512^2 .
It is a cyclic number.
It is not a de Polignac number, because 13430050020313 - 25 = 13430050020281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13430050020353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10283345458 + ... + 10283346763.
It is an arithmetic number, because the mean of its divisors is an integer number (3362654178297).
Almost surely, 213430050020313 is an apocalyptic number.
It is an amenable number.
13430050020313 is a deficient number, since it is larger than the sum of its proper divisors (20566692875).
13430050020313 is an equidigital number, since it uses as much as digits as its factorization.
13430050020313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20566692874.
The product of its (nonzero) digits is 3240, while the sum is 25.
Adding to 13430050020313 its reverse (31302005003431), we get a palindrome (44732055023744).
The spelling of 13430050020313 in words is "thirteen trillion, four hundred thirty billion, fifty million, twenty thousand, three hundred thirteen".
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