Base | Representation |
---|---|
bin | 11110100010010101111101… |
… | …101000000000111011101001 |
3 | 122121112002111021021121210121 |
4 | 132202111331220000323221 |
5 | 120100343322121121301 |
6 | 1153345121345443241 |
7 | 40200646611463666 |
oct | 3642257550007351 |
9 | 577462437247717 |
10 | 134301440020201 |
11 | 39879a14729633 |
12 | 13090628640521 |
13 | 59c2757630a7c |
14 | 252431d9aca6d |
15 | 107d74e3603a1 |
hex | 7a257da00ee9 |
134301440020201 has 2 divisors, whose sum is σ = 134301440020202. Its totient is φ = 134301440020200.
The previous prime is 134301440020147. The next prime is 134301440020213. The reversal of 134301440020201 is 102020044103431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 106732639660201 + 27568800360000 = 10331149^2 + 5250600^2 .
It is a cyclic number.
It is not a de Polignac number, because 134301440020201 - 223 = 134301431631593 is a prime.
It is not a weakly prime, because it can be changed into another prime (134301440020291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67150720010100 + 67150720010101.
It is an arithmetic number, because the mean of its divisors is an integer number (67150720010101).
Almost surely, 2134301440020201 is an apocalyptic number.
It is an amenable number.
134301440020201 is a deficient number, since it is larger than the sum of its proper divisors (1).
134301440020201 is an equidigital number, since it uses as much as digits as its factorization.
134301440020201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134301440020201 its reverse (102020044103431), we get a palindrome (236321484123632).
The spelling of 134301440020201 in words is "one hundred thirty-four trillion, three hundred one billion, four hundred forty million, twenty thousand, two hundred one".
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