Base | Representation |
---|---|
bin | 11110100010010110111110… |
… | …111110100101010110000010 |
3 | 122121112012022200102022100101 |
4 | 132202112332332211112002 |
5 | 120100403043313034204 |
6 | 1153345422234113014 |
7 | 40201016024152345 |
oct | 3642267676452602 |
9 | 577465280368311 |
10 | 134302536455554 |
11 | 3987a427629755 |
12 | 1309089387b76a |
13 | 59c28a083409c |
14 | 25243c546045c |
15 | 107d7b573eea4 |
hex | 7a25befa5582 |
134302536455554 has 4 divisors (see below), whose sum is σ = 201453804683334. Its totient is φ = 67151268227776.
The previous prime is 134302536455543. The next prime is 134302536455569. The reversal of 134302536455554 is 455554635203431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 128898896823225 + 5403639632329 = 11353365^2 + 2324573^2 .
It is a super-2 number, since 2×1343025364555542 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134302536455495 and 134302536455504.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33575634113887 + ... + 33575634113890.
Almost surely, 2134302536455554 is an apocalyptic number.
134302536455554 is a deficient number, since it is larger than the sum of its proper divisors (67151268227780).
134302536455554 is an equidigital number, since it uses as much as digits as its factorization.
134302536455554 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67151268227779.
The product of its (nonzero) digits is 64800000, while the sum is 55.
The spelling of 134302536455554 in words is "one hundred thirty-four trillion, three hundred two billion, five hundred thirty-six million, four hundred fifty-five thousand, five hundred fifty-four".
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