Base | Representation |
---|---|
bin | 1100001101110000010000… |
… | …1001110010110110101011 |
3 | 1202112221021221000120002112 |
4 | 3003130010021302312223 |
5 | 3230021011144123201 |
6 | 44321504440552535 |
7 | 2554213430623025 |
oct | 303340411626653 |
9 | 52487257016075 |
10 | 13430432411051 |
11 | 43088a5a68a27 |
12 | 160aaa878274b |
13 | 76563b13a676 |
14 | 346071c33015 |
15 | 184552b210bb |
hex | c3704272dab |
13430432411051 has 4 divisors (see below), whose sum is σ = 13494083749704. Its totient is φ = 13366781072400.
The previous prime is 13430432411023. The next prime is 13430432411063. The reversal of 13430432411051 is 15011423403431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13430432411051 - 222 = 13430428216747 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13430432410999 and 13430432411017.
It is not an unprimeable number, because it can be changed into a prime (13430432419051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31825669010 + ... + 31825669431.
It is an arithmetic number, because the mean of its divisors is an integer number (3373520937426).
Almost surely, 213430432411051 is an apocalyptic number.
13430432411051 is a deficient number, since it is larger than the sum of its proper divisors (63651338653).
13430432411051 is an equidigital number, since it uses as much as digits as its factorization.
13430432411051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63651338652.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 13430432411051 its reverse (15011423403431), we get a palindrome (28441855814482).
The spelling of 13430432411051 in words is "thirteen trillion, four hundred thirty billion, four hundred thirty-two million, four hundred eleven thousand, fifty-one".
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