Base | Representation |
---|---|
bin | 11001000001000010… |
… | …11010111111100001 |
3 | 1021122222220211020101 |
4 | 30200201122333201 |
5 | 210001204042423 |
6 | 10100410542401 |
7 | 653551441063 |
oct | 144041327741 |
9 | 37588824211 |
10 | 13430534113 |
11 | 5772206077 |
12 | 2729a37a01 |
13 | 1360644409 |
14 | 9159db733 |
15 | 5391477ad |
hex | 32085afe1 |
13430534113 has 2 divisors, whose sum is σ = 13430534114. Its totient is φ = 13430534112.
The previous prime is 13430534101. The next prime is 13430534171. The reversal of 13430534113 is 31143503431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13352264704 + 78269409 = 115552^2 + 8847^2 .
It is an emirp because it is prime and its reverse (31143503431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13430534113 - 213 = 13430525921 is a prime.
It is not a weakly prime, because it can be changed into another prime (13430534413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715267056 + 6715267057.
It is an arithmetic number, because the mean of its divisors is an integer number (6715267057).
Almost surely, 213430534113 is an apocalyptic number.
It is an amenable number.
13430534113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13430534113 is an equidigital number, since it uses as much as digits as its factorization.
13430534113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
The spelling of 13430534113 in words is "thirteen billion, four hundred thirty million, five hundred thirty-four thousand, one hundred thirteen".
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