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1343100144523 = 2946313798087
BaseRepresentation
bin10011100010110111000…
…000011100101110001011
311202101202221212122112011
4103202313000130232023
5134001132114111043
62505002305200351
7166015162601404
oct23426700345613
94671687778464
101343100144523
11478673020745
121983756300b7
1399866525737
144901378a9ab
1524e0cb8359d
hex138b701cb8b

1343100144523 has 4 divisors (see below), whose sum is σ = 1389413942640. Its totient is φ = 1296786346408.

The previous prime is 1343100144499. The next prime is 1343100144527. The reversal of 1343100144523 is 3254410013431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1343100144523 - 233 = 1334510209931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343100144527) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23156899015 + ... + 23156899072.

It is an arithmetic number, because the mean of its divisors is an integer number (347353485660).

Almost surely, 21343100144523 is an apocalyptic number.

1343100144523 is a deficient number, since it is larger than the sum of its proper divisors (46313798117).

1343100144523 is an equidigital number, since it uses as much as digits as its factorization.

1343100144523 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46313798116.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1343100144523 its reverse (3254410013431), we get a palindrome (4597510157954).

The spelling of 1343100144523 in words is "one trillion, three hundred forty-three billion, one hundred million, one hundred forty-four thousand, five hundred twenty-three".

Divisors: 1 29 46313798087 1343100144523