Base | Representation |
---|---|
bin | 1100001101110010011011… |
… | …0001010111101111101001 |
3 | 1202112222210101220020222221 |
4 | 3003130212301113233221 |
5 | 3230023203340223423 |
6 | 44322042225314041 |
7 | 2554234012424461 |
oct | 303344661275751 |
9 | 52488711806887 |
10 | 13431013211113 |
11 | 43090738a2683 |
12 | 160b02b195921 |
13 | 765701573044 |
14 | 3460c901cba1 |
15 | 184588ae9e5d |
hex | c3726c57be9 |
13431013211113 has 2 divisors, whose sum is σ = 13431013211114. Its totient is φ = 13431013211112.
The previous prime is 13431013211089. The next prime is 13431013211129. The reversal of 13431013211113 is 31111231013431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12619062638224 + 811950572889 = 3552332^2 + 901083^2 .
It is a cyclic number.
It is not a de Polignac number, because 13431013211113 - 229 = 13430476340201 is a prime.
It is not a weakly prime, because it can be changed into another prime (13431013211153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6715506605556 + 6715506605557.
It is an arithmetic number, because the mean of its divisors is an integer number (6715506605557).
Almost surely, 213431013211113 is an apocalyptic number.
It is an amenable number.
13431013211113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13431013211113 is an equidigital number, since it uses as much as digits as its factorization.
13431013211113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 13431013211113 its reverse (31111231013431), we get a palindrome (44542244224544).
The spelling of 13431013211113 in words is "thirteen trillion, four hundred thirty-one billion, thirteen million, two hundred eleven thousand, one hundred thirteen".
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