Base | Representation |
---|---|
bin | 1100001101110010011011… |
… | …0101111101001011110010 |
3 | 1202112222210111011022201211 |
4 | 3003130212311331023302 |
5 | 3230023204142204132 |
6 | 44322042311150334 |
7 | 2554234025561602 |
oct | 303344665751362 |
9 | 52488714138654 |
10 | 13431014413042 |
11 | 4309074543706 |
12 | 160b02b6753aa |
13 | 7657018a4145 |
14 | 3460c9252c02 |
15 | 184588c86147 |
hex | c3726d7d2f2 |
13431014413042 has 4 divisors (see below), whose sum is σ = 20146521619566. Its totient is φ = 6715507206520.
The previous prime is 13431014412941. The next prime is 13431014413097. The reversal of 13431014413042 is 24031441013431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9547982580361 + 3883031832681 = 3089981^2 + 1970541^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13431014412995 and 13431014413013.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3357753603259 + ... + 3357753603262.
Almost surely, 213431014413042 is an apocalyptic number.
13431014413042 is a deficient number, since it is larger than the sum of its proper divisors (6715507206524).
13431014413042 is an equidigital number, since it uses as much as digits as its factorization.
13431014413042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6715507206523.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 13431014413042 its reverse (24031441013431), we get a palindrome (37462455426473).
The spelling of 13431014413042 in words is "thirteen trillion, four hundred thirty-one billion, fourteen million, four hundred thirteen thousand, forty-two".
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