Base | Representation |
---|---|
bin | 10011100010110111000… |
… | …110000000101101110001 |
3 | 11202101210001121201201201 |
4 | 103202313012000231301 |
5 | 134001133002241143 |
6 | 2505002400331201 |
7 | 166015211153515 |
oct | 23426706005561 |
9 | 4671701551651 |
10 | 1343101602673 |
11 | 478673927226 |
12 | 198376013b01 |
13 | 9986691634c |
14 | 49013a4a145 |
15 | 24e0cd7064d |
hex | 138b7180b71 |
1343101602673 has 2 divisors, whose sum is σ = 1343101602674. Its totient is φ = 1343101602672.
The previous prime is 1343101602607. The next prime is 1343101602719. The reversal of 1343101602673 is 3762061013431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1173792395889 + 169309206784 = 1083417^2 + 411472^2 .
It is a cyclic number.
It is not a de Polignac number, because 1343101602673 - 213 = 1343101594481 is a prime.
It is not a weakly prime, because it can be changed into another prime (1343101602173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671550801336 + 671550801337.
It is an arithmetic number, because the mean of its divisors is an integer number (671550801337).
Almost surely, 21343101602673 is an apocalyptic number.
It is an amenable number.
1343101602673 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343101602673 is an equidigital number, since it uses as much as digits as its factorization.
1343101602673 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 37.
The spelling of 1343101602673 in words is "one trillion, three hundred forty-three billion, one hundred one million, six hundred two thousand, six hundred seventy-three".
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