13431034134241 has 4 divisors (see below), whose sum is σ = 13446176225472. Its totient is φ = 13415892043012.

The previous prime is 13431034134227. The next prime is 13431034134257. The reversal of 13431034134241 is 14243143013431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13431034134241 - 2⁵ = 13431034134209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13431034134197 and 13431034134206.

It is not an unprimeable number, because it can be changed into a prime (13431034134541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7571044285 + ... + 7571046058.

It is an arithmetic number, because the mean of its divisors is an integer number (3361544056368).

Almost surely, 2^{13431034134241} is an apocalyptic number.

It is an amenable number.

13431034134241 is a deficient number, since it is larger than the sum of its proper divisors (15142091231).

13431034134241 is an equidigital number, since it uses as much as digits as its factorization.

13431034134241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15142091230.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 13431034134241 its reverse (14243143013431), we get a palindrome (27674177147672).

The spelling of 13431034134241 in words is "thirteen trillion, four hundred thirty-one billion, thirty-four million, one hundred thirty-four thousand, two hundred forty-one".