Base | Representation |
---|---|
bin | 11110100010011110111000… |
… | …101111010100101001100011 |
3 | 122121120000020000221201120112 |
4 | 132202132320233110221203 |
5 | 120101022433030220212 |
6 | 1153353344231001535 |
7 | 40201436216602136 |
oct | 3642367057245143 |
9 | 577500200851515 |
10 | 134311021726307 |
11 | 39882a91313208 |
12 | 130924615092ab |
13 | 59c3623772c5a |
14 | 252498c36821d |
15 | 107db10644422 |
hex | 7a27b8bd4a63 |
134311021726307 has 2 divisors, whose sum is σ = 134311021726308. Its totient is φ = 134311021726306.
The previous prime is 134311021726261. The next prime is 134311021726333. The reversal of 134311021726307 is 703627120113431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134311021726307 - 212 = 134311021722211 is a prime.
It is not a weakly prime, because it can be changed into another prime (134311021726337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67155510863153 + 67155510863154.
It is an arithmetic number, because the mean of its divisors is an integer number (67155510863154).
Almost surely, 2134311021726307 is an apocalyptic number.
134311021726307 is a deficient number, since it is larger than the sum of its proper divisors (1).
134311021726307 is an equidigital number, since it uses as much as digits as its factorization.
134311021726307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 127008, while the sum is 41.
Adding to 134311021726307 its reverse (703627120113431), we get a palindrome (837938141839738).
The spelling of 134311021726307 in words is "one hundred thirty-four trillion, three hundred eleven billion, twenty-one million, seven hundred twenty-six thousand, three hundred seven".
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