Base | Representation |
---|---|
bin | 11001000001000111… |
… | …01000001100000011 |
3 | 1021200001000012120022 |
4 | 30200203220030003 |
5 | 210001331044301 |
6 | 10100431204055 |
7 | 653556400151 |
oct | 144043501403 |
9 | 37601005508 |
10 | 13431112451 |
11 | 5772570639 |
12 | 272a07662b |
13 | 13607b7723 |
14 | 915b0c3d1 |
15 | 53920dd1b |
hex | 3208e8303 |
13431112451 has 4 divisors (see below), whose sum is σ = 13432406592. Its totient is φ = 13429818312.
The previous prime is 13431112439. The next prime is 13431112477. The reversal of 13431112451 is 15421113431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15421113431 = 19 ⋅811637549.
It is a cyclic number.
It is not a de Polignac number, because 13431112451 - 210 = 13431111427 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13431112451.
It is not an unprimeable number, because it can be changed into a prime (13431112481) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 631376 + ... + 652301.
It is an arithmetic number, because the mean of its divisors is an integer number (3358101648).
Almost surely, 213431112451 is an apocalyptic number.
13431112451 is a deficient number, since it is larger than the sum of its proper divisors (1294141).
13431112451 is a wasteful number, since it uses less digits than its factorization.
13431112451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1294140.
The product of its digits is 1440, while the sum is 26.
Adding to 13431112451 its reverse (15421113431), we get a palindrome (28852225882).
The spelling of 13431112451 in words is "thirteen billion, four hundred thirty-one million, one hundred twelve thousand, four hundred fifty-one".
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