13431144033 has 10 divisors (see below), whose sum is σ = 20063807874. Its totient is φ = 8954095968.

The previous prime is 13431144019. The next prime is 13431144073. The reversal of 13431144033 is 33044113431.

13431144033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 7429233249 + 6001910784 = 86193^2 + 77472^2 .

It is not a de Polignac number, because 13431144033 - 2⁶ = 13431143969 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13431143988 and 13431144006.

It is not an unprimeable number, because it can be changed into a prime (13431144073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 82908216 + ... + 82908377.

Almost surely, 2^13431144033 is an apocalyptic number.

It is an amenable number.

13431144033 is a deficient number, since it is larger than the sum of its proper divisors (6632663841).

13431144033 is an equidigital number, since it uses as much as digits as its factorization.

13431144033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 165816605 (or 165816596 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13431144033 its reverse (33044113431), we get a palindrome (46475257464).

It can be divided in two parts, 13431 and 144033, that added together give a cube (157464 = 54³).

The spelling of 13431144033 in words is "thirteen billion, four hundred thirty-one million, one hundred forty-four thousand, thirty-three".