Base | Representation |
---|---|
bin | 11110100010011111110100… |
… | …100001000000001101100101 |
3 | 122121120002210221001021020212 |
4 | 132202133310201000031211 |
5 | 120101032011244334131 |
6 | 1153354031534105205 |
7 | 40201503115124246 |
oct | 3642376441001545 |
9 | 577502727037225 |
10 | 134312024605541 |
11 | 39883456423222 |
12 | 130926a134b205 |
13 | 59c375347a813 |
14 | 2524a45624ccd |
15 | 107db6d6e3a2b |
hex | 7a27f4840365 |
134312024605541 has 16 divisors (see below), whose sum is σ = 139991102160000. Its totient is φ = 128705660596800.
The previous prime is 134312024605511. The next prime is 134312024605559. The reversal of 134312024605541 is 145506420213431.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134312024605541 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134312024605511) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23020145 + ... + 28258646.
It is an arithmetic number, because the mean of its divisors is an integer number (8749443885000).
Almost surely, 2134312024605541 is an apocalyptic number.
It is an amenable number.
134312024605541 is a deficient number, since it is larger than the sum of its proper divisors (5679077554459).
134312024605541 is a wasteful number, since it uses less digits than its factorization.
134312024605541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51279500.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 134312024605541 its reverse (145506420213431), we get a palindrome (279818444818972).
The spelling of 134312024605541 in words is "one hundred thirty-four trillion, three hundred twelve billion, twenty-four million, six hundred five thousand, five hundred forty-one".
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