Search a number
-
+
1343202104441 = 1917032471751
BaseRepresentation
bin10011100010111101000…
…101011001010001111001
311202102001001201202020102
4103202331011121101321
5134001334214320231
62505020350405145
7166020541335551
oct23427505312171
94672031652212
101343202104441
1147871563073a
121983a38007b5
13998816a4352
144902312c161
1524e16ac3acb
hex138bd159479

1343202104441 has 4 divisors (see below), whose sum is σ = 1350234576384. Its totient is φ = 1336169632500.

The previous prime is 1343202104411. The next prime is 1343202104591. The reversal of 1343202104441 is 1444012023431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1343202104441 - 226 = 1343134995577 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1343202104411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3516235685 + ... + 3516236066.

It is an arithmetic number, because the mean of its divisors is an integer number (337558644096).

Almost surely, 21343202104441 is an apocalyptic number.

It is an amenable number.

1343202104441 is a deficient number, since it is larger than the sum of its proper divisors (7032471943).

1343202104441 is an equidigital number, since it uses as much as digits as its factorization.

1343202104441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7032471942.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 1343202104441 its reverse (1444012023431), we get a palindrome (2787214127872).

The spelling of 1343202104441 in words is "one trillion, three hundred forty-three billion, two hundred two million, one hundred four thousand, four hundred forty-one".

Divisors: 1 191 7032471751 1343202104441