Base | Representation |
---|---|
bin | 11110100010101000010100… |
… | …000001011011100000101011 |
3 | 122121120222100102011112002102 |
4 | 132202220110001123200223 |
5 | 120101204200120244001 |
6 | 1153402140431524015 |
7 | 40202245100261123 |
oct | 3642502401334053 |
9 | 577528312145072 |
10 | 134321143134251 |
11 | 39887305610867 |
12 | 1309440708960b |
13 | 59c457765b138 |
14 | 252526c691c83 |
15 | 107e003ed4e6b |
hex | 7a2a1405b82b |
134321143134251 has 2 divisors, whose sum is σ = 134321143134252. Its totient is φ = 134321143134250.
The previous prime is 134321143134223. The next prime is 134321143134359. The reversal of 134321143134251 is 152431341123431.
It is a weak prime.
It is an emirp because it is prime and its reverse (152431341123431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134321143134251 - 234 = 134303963265067 is a prime.
It is not a weakly prime, because it can be changed into another prime (134321143124251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67160571567125 + 67160571567126.
It is an arithmetic number, because the mean of its divisors is an integer number (67160571567126).
Almost surely, 2134321143134251 is an apocalyptic number.
134321143134251 is a deficient number, since it is larger than the sum of its proper divisors (1).
134321143134251 is an equidigital number, since it uses as much as digits as its factorization.
134321143134251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 103680, while the sum is 38.
Adding to 134321143134251 its reverse (152431341123431), we get a palindrome (286752484257682).
The spelling of 134321143134251 in words is "one hundred thirty-four trillion, three hundred twenty-one billion, one hundred forty-three million, one hundred thirty-four thousand, two hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.083 sec. • engine limits •