Base | Representation |
---|---|
bin | 111110100011000111… |
… | …1011000101001110001 |
3 | 110211201011100011020122 |
4 | 1331012033120221301 |
5 | 4200043020040213 |
6 | 141412403420025 |
7 | 12463430524601 |
oct | 1750617305161 |
9 | 424634304218 |
10 | 134322424433 |
11 | 51a6956362a |
12 | 22048384615 |
13 | c888545b22 |
14 | 670358cc01 |
15 | 3762576d08 |
hex | 1f463d8a71 |
134322424433 has 2 divisors, whose sum is σ = 134322424434. Its totient is φ = 134322424432.
The previous prime is 134322424421. The next prime is 134322424447. The reversal of 134322424433 is 334424223431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73366764769 + 60955659664 = 270863^2 + 246892^2 .
It is a cyclic number.
It is not a de Polignac number, because 134322424433 - 24 = 134322424417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134322424393 and 134322424402.
It is not a weakly prime, because it can be changed into another prime (134322424463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67161212216 + 67161212217.
It is an arithmetic number, because the mean of its divisors is an integer number (67161212217).
Almost surely, 2134322424433 is an apocalyptic number.
It is an amenable number.
134322424433 is a deficient number, since it is larger than the sum of its proper divisors (1).
134322424433 is an equidigital number, since it uses as much as digits as its factorization.
134322424433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 165888, while the sum is 35.
Adding to 134322424433 its reverse (334424223431), we get a palindrome (468746647864).
The spelling of 134322424433 in words is "one hundred thirty-four billion, three hundred twenty-two million, four hundred twenty-four thousand, four hundred thirty-three".
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