13432322000401 has 2 divisors, whose sum is σ = 13432322000402. Its totient is φ = 13432322000400.

The previous prime is 13432322000393. The next prime is 13432322000411. The reversal of 13432322000401 is 10400022323431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12657656217600 + 774665782801 = 3557760^2 + 880151^2 .

It is a cyclic number.

It is not a de Polignac number, because 13432322000401 - 2³ = 13432322000393 is a prime.

It is not a weakly prime, because it can be changed into another prime (13432322000411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716161000200 + 6716161000201.

It is an arithmetic number, because the mean of its divisors is an integer number (6716161000201).

Almost surely, 2^{13432322000401} is an apocalyptic number.

It is an amenable number.

13432322000401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13432322000401 is an equidigital number, since it uses as much as digits as its factorization.

13432322000401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 13432322000401 its reverse (10400022323431), we get a palindrome (23832344323832).

The spelling of 13432322000401 in words is "thirteen trillion, four hundred thirty-two billion, three hundred twenty-two million, four hundred one", and thus it is an aban number.