Base | Representation |
---|---|
bin | 111110100011001001… |
… | …0110100000011111011 |
3 | 110211201020000211000202 |
4 | 1331012102310003323 |
5 | 4200043232320011 |
6 | 141412434552415 |
7 | 12463441256654 |
oct | 1750622640373 |
9 | 424636024022 |
10 | 134323323131 |
11 | 51a6a017858 |
12 | 2204873870b |
13 | c88879bbba |
14 | 670374452b |
15 | 37626a323b |
hex | 1f464b40fb |
134323323131 has 2 divisors, whose sum is σ = 134323323132. Its totient is φ = 134323323130.
The previous prime is 134323323107. The next prime is 134323323163. The reversal of 134323323131 is 131323323431.
It is a weak prime.
It is an emirp because it is prime and its reverse (131323323431) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134323323131 is a prime.
It is a super-2 number, since 2×1343233231312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134323323094 and 134323323103.
It is not a weakly prime, because it can be changed into another prime (134323323731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67161661565 + 67161661566.
It is an arithmetic number, because the mean of its divisors is an integer number (67161661566).
Almost surely, 2134323323131 is an apocalyptic number.
134323323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
134323323131 is an equidigital number, since it uses as much as digits as its factorization.
134323323131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11664, while the sum is 29.
Adding to 134323323131 its reverse (131323323431), we get a palindrome (265646646562).
The spelling of 134323323131 in words is "one hundred thirty-four billion, three hundred twenty-three million, three hundred twenty-three thousand, one hundred thirty-one".
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