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13432503144497 is a prime number
BaseRepresentation
bin1100001101110111111110…
…0101000001000000110001
31202120010122020110201100212
43003131333211001000301
53230034231301110442
644322450131553505
72554315643564543
oct303357745010061
952503566421325
1013432503144497
114309768927688
12160b38615b895
137658ab14c328
143461cac61693
15184624806a82
hexc377f941031

13432503144497 has 2 divisors, whose sum is σ = 13432503144498. Its totient is φ = 13432503144496.

The previous prime is 13432503144427. The next prime is 13432503144503. The reversal of 13432503144497 is 79444130523431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11517002856241 + 1915500288256 = 3393671^2 + 1384016^2 .

It is a cyclic number.

It is not a de Polignac number, because 13432503144497 - 210 = 13432503143473 is a prime.

It is a super-2 number, since 2×134325031444972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13432503144427) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6716251572248 + 6716251572249.

It is an arithmetic number, because the mean of its divisors is an integer number (6716251572249).

Almost surely, 213432503144497 is an apocalyptic number.

It is an amenable number.

13432503144497 is a deficient number, since it is larger than the sum of its proper divisors (1).

13432503144497 is an equidigital number, since it uses as much as digits as its factorization.

13432503144497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 50.

The spelling of 13432503144497 in words is "thirteen trillion, four hundred thirty-two billion, five hundred three million, one hundred forty-four thousand, four hundred ninety-seven".