Search a number
-
+
13433045535321 = 34477681845107
BaseRepresentation
bin1100001101111001111111…
…1010000100101001011001
31202120012001001002000200220
43003132133322010221121
53230041334124112241
644323020025150253
72554335251045106
oct303363772045131
952505031060626
1013433045535321
114309a17007965
12160b4b792b389
13765966627249
1434623cccdaad
15184657245166
hexc379fe84a59

13433045535321 has 4 divisors (see below), whose sum is σ = 17910727380432. Its totient is φ = 8955363690212.

The previous prime is 13433045535317. The next prime is 13433045535331. The reversal of 13433045535321 is 12353554033431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13433045535321 - 22 = 13433045535317 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13433045535331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2238840922551 + ... + 2238840922556.

It is an arithmetic number, because the mean of its divisors is an integer number (4477681845108).

Almost surely, 213433045535321 is an apocalyptic number.

It is an amenable number.

13433045535321 is a deficient number, since it is larger than the sum of its proper divisors (4477681845111).

13433045535321 is an equidigital number, since it uses as much as digits as its factorization.

13433045535321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4477681845110.

The product of its (nonzero) digits is 972000, while the sum is 42.

Adding to 13433045535321 its reverse (12353554033431), we get a palindrome (25786599568752).

The spelling of 13433045535321 in words is "thirteen trillion, four hundred thirty-three billion, forty-five million, five hundred thirty-five thousand, three hundred twenty-one".

Divisors: 1 3 4477681845107 13433045535321