134331010000027 has 2 divisors, whose sum is σ = 134331010000028. Its totient is φ = 134331010000026.

The previous prime is 134331010000013. The next prime is 134331010000039. The reversal of 134331010000027 is 720000010133431.

It is a strong prime.

It is an emirp because it is prime and its reverse (720000010133431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134331010000027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134331009999956 and 134331010000010.

It is not a weakly prime, because it can be changed into another prime (134331010006027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165505000013 + 67165505000014.

It is an arithmetic number, because the mean of its divisors is an integer number (67165505000014).

Almost surely, 2^{134331010000027} is an apocalyptic number.

134331010000027 is a deficient number, since it is larger than the sum of its proper divisors (1).

134331010000027 is an equidigital number, since it uses as much as digits as its factorization.

134331010000027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 134331010000027 its reverse (720000010133431), we get a palindrome (854331020133458).

The spelling of 134331010000027 in words is "one hundred thirty-four trillion, three hundred thirty-one billion, ten million, twenty-seven", and thus it is an aban number.