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134331350561 is a prime number
BaseRepresentation
bin111110100011011000…
…1011011111000100001
3110211201210010122120222
41331012301123320201
54200102311204221
6141413323012425
712463566432362
oct1750661337041
9424653118528
10134331350561
1151a735aa9a1
122204b36a115
13c88a34c965
146704833b69
15376323b9ab
hex1f46c5be21

134331350561 has 2 divisors, whose sum is σ = 134331350562. Its totient is φ = 134331350560.

The previous prime is 134331350557. The next prime is 134331350579. The reversal of 134331350561 is 165053133431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127248444961 + 7082905600 = 356719^2 + 84160^2 .

It is a cyclic number.

It is not a de Polignac number, because 134331350561 - 22 = 134331350557 is a prime.

It is not a weakly prime, because it can be changed into another prime (134331350521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67165675280 + 67165675281.

It is an arithmetic number, because the mean of its divisors is an integer number (67165675281).

Almost surely, 2134331350561 is an apocalyptic number.

It is an amenable number.

134331350561 is a deficient number, since it is larger than the sum of its proper divisors (1).

134331350561 is an equidigital number, since it uses as much as digits as its factorization.

134331350561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 35.

Adding to 134331350561 its reverse (165053133431), we get a palindrome (299384483992).

The spelling of 134331350561 in words is "one hundred thirty-four billion, three hundred thirty-one million, three hundred fifty thousand, five hundred sixty-one".