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134333054202307 is a prime number
BaseRepresentation
bin11110100010110011011001…
…111110100011000111000011
3122121122010002111221110202011
4132202303121332203013003
5120101403043333433212
61153411430403233351
740203146211551062
oct3642633176430703
9577563074843664
10134333054202307
1139891368050564
1213096790078857
1359c5725255bbc
142525a7c5601d9
15107e49ea3a4a7
hex7a2cd9fa31c3

134333054202307 has 2 divisors, whose sum is σ = 134333054202308. Its totient is φ = 134333054202306.

The previous prime is 134333054202301. The next prime is 134333054202343. The reversal of 134333054202307 is 703202450333431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134333054202307 - 223 = 134333045813699 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134333054202307.

It is not a weakly prime, because it can be changed into another prime (134333054202301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67166527101153 + 67166527101154.

It is an arithmetic number, because the mean of its divisors is an integer number (67166527101154).

Almost surely, 2134333054202307 is an apocalyptic number.

134333054202307 is a deficient number, since it is larger than the sum of its proper divisors (1).

134333054202307 is an equidigital number, since it uses as much as digits as its factorization.

134333054202307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 544320, while the sum is 40.

The spelling of 134333054202307 in words is "one hundred thirty-four trillion, three hundred thirty-three billion, fifty-four million, two hundred two thousand, three hundred seven".