Base | Representation |
---|---|
bin | 11110100010110100011010… |
… | …100011000011110000011010 |
3 | 122121122012220000101110102202 |
4 | 132202310122203003300122 |
5 | 120101412303200440114 |
6 | 1153412130102330202 |
7 | 40203215104553162 |
oct | 3642643243036032 |
9 | 577565800343382 |
10 | 134334137515034 |
11 | 398918735a8436 |
12 | 13096a32a29962 |
13 | 59c5868813252 |
14 | 2525b423975a2 |
15 | 107e514bc6cde |
hex | 7a2d1a8c3c1a |
134334137515034 has 8 divisors (see below), whose sum is σ = 201512043805140. Its totient is φ = 67163456246656.
The previous prime is 134334137515001. The next prime is 134334137515063. The reversal of 134334137515034 is 430515731433431.
It can be written as a sum of positive squares in 2 ways, for example, as 130094668869025 + 4239468646009 = 11405905^2 + 2058997^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 134334137515034.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1806208949 + ... + 1806283320.
Almost surely, 2134334137515034 is an apocalyptic number.
134334137515034 is a deficient number, since it is larger than the sum of its proper divisors (67177906290106).
134334137515034 is a wasteful number, since it uses less digits than its factorization.
134334137515034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3612510864.
The product of its (nonzero) digits is 2721600, while the sum is 47.
Adding to 134334137515034 its reverse (430515731433431), we get a palindrome (564849868948465).
The spelling of 134334137515034 in words is "one hundred thirty-four trillion, three hundred thirty-four billion, one hundred thirty-seven million, five hundred fifteen thousand, thirty-four".
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