13433414431241 has 8 divisors (see below), whose sum is σ = 15354240591360. Its totient is φ = 11513030010048.

The previous prime is 13433414431231. The next prime is 13433414431277. The reversal of 13433414431241 is 14213441433431.

13433414431241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13433414431241 - 2¹⁰ = 13433414430217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13433414431195 and 13433414431204.

It is not an unprimeable number, because it can be changed into a prime (13433414431231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 110369561 + ... + 110491206.

It is an arithmetic number, because the mean of its divisors is an integer number (1919280073920).

Almost surely, 2^{13433414431241} is an apocalyptic number.

It is an amenable number.

13433414431241 is a deficient number, since it is larger than the sum of its proper divisors (1920826160119).

13433414431241 is an equidigital number, since it uses as much as digits as its factorization.

13433414431241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 220869463.

The product of its digits is 165888, while the sum is 38.

Adding to 13433414431241 its reverse (14213441433431), we get a palindrome (27646855864672).

The spelling of 13433414431241 in words is "thirteen trillion, four hundred thirty-three billion, four hundred fourteen million, four hundred thirty-one thousand, two hundred forty-one".