Base | Representation |
---|---|
bin | 1100001101111101111011… |
… | …1101010000001000111010 |
3 | 1202120021202202111201220210 |
4 | 3003133132331100020322 |
5 | 3230101020423132214 |
6 | 44323313013331550 |
7 | 2554403414142450 |
oct | 303373675201072 |
9 | 52507682451823 |
10 | 13434103333434 |
11 | 430a40a118283 |
12 | 160b752036bb6 |
13 | 765aa48200a4 |
14 | 3462dd5a49d0 |
15 | 1846ba041b59 |
hex | c37def5023a |
13434103333434 has 32 divisors (see below), whose sum is σ = 30720784314240. Its totient is φ = 3836532436992.
The previous prime is 13434103333429. The next prime is 13434103333447. The reversal of 13434103333434 is 43433330143431.
It is a happy number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13434103333392 and 13434103333401.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 74191879 + ... + 74372730.
It is an arithmetic number, because the mean of its divisors is an integer number (960024509820).
Almost surely, 213434103333434 is an apocalyptic number.
13434103333434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13434103333434 is an abundant number, since it is smaller than the sum of its proper divisors (17286680980806).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13434103333434 is a wasteful number, since it uses less digits than its factorization.
13434103333434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148566774.
The product of its (nonzero) digits is 559872, while the sum is 39.
Adding to 13434103333434 its reverse (43433330143431), we get a palindrome (56867433476865).
The spelling of 13434103333434 in words is "thirteen trillion, four hundred thirty-four billion, one hundred three million, three hundred thirty-three thousand, four hundred thirty-four".
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