13434141133441 has 4 divisors (see below), whose sum is σ = 15353304152512. Its totient is φ = 11514978114372.

The previous prime is 13434141133403. The next prime is 13434141133453. The reversal of 13434141133441 is 14433114143431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13434141133441 - 2¹⁵ = 13434141100673 is a prime.

It is a super-2 number, since 2×13434141133441² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13434141133441.

It is not an unprimeable number, because it can be changed into a prime (13434141134441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 959581509525 + ... + 959581509538.

It is an arithmetic number, because the mean of its divisors is an integer number (3838326038128).

Almost surely, 2^{13434141133441} is an apocalyptic number.

It is an amenable number.

13434141133441 is a deficient number, since it is larger than the sum of its proper divisors (1919163019071).

13434141133441 is an equidigital number, since it uses as much as digits as its factorization.

13434141133441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919163019070.

The product of its digits is 82944, while the sum is 37.

Adding to 13434141133441 its reverse (14433114143431), we get a palindrome (27867255276872).

The spelling of 13434141133441 in words is "thirteen trillion, four hundred thirty-four billion, one hundred forty-one million, one hundred thirty-three thousand, four hundred forty-one".