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13434225001 = 128310470947
BaseRepresentation
bin11001000001011111…
…00000000101101001
31021200020212100011221
430200233200011221
5210003130200001
610101022022041
7653625012511
oct144057400551
937606770157
1013434225001
1157742a709a
12272b117921
131361337382
149162bc841
155396261a1
hex320be0169

13434225001 has 4 divisors (see below), whose sum is σ = 13444697232. Its totient is φ = 13423752772.

The previous prime is 13434224983. The next prime is 13434225019. The reversal of 13434225001 is 10052243431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (13434224983) and next prime (13434225019).

It is a cyclic number.

It is not a de Polignac number, because 13434225001 - 223 = 13425836393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13434225041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5234191 + ... + 5236756.

It is an arithmetic number, because the mean of its divisors is an integer number (3361174308).

Almost surely, 213434225001 is an apocalyptic number.

It is an amenable number.

13434225001 is a deficient number, since it is larger than the sum of its proper divisors (10472231).

13434225001 is a wasteful number, since it uses less digits than its factorization.

13434225001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10472230.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13434225001 its reverse (10052243431), we get a palindrome (23486468432).

The spelling of 13434225001 in words is "thirteen billion, four hundred thirty-four million, two hundred twenty-five thousand, one".

Divisors: 1 1283 10470947 13434225001