Search a number
-
+
134342310024457 is a prime number
BaseRepresentation
bin11110100010111100000001…
…101010101101010100001001
3122121122222222120101221202221
4132202330001222231110021
5120102031022331240312
61153420001043454041
740203624452003233
oct3642740152552411
9577588876357687
10134342310024457
1139895287791757
1213098533987321
1359c656ba06942
1425262b9929253
15107e8423eb207
hex7a2f01aad509

134342310024457 has 2 divisors, whose sum is σ = 134342310024458. Its totient is φ = 134342310024456.

The previous prime is 134342310024431. The next prime is 134342310024463. The reversal of 134342310024457 is 754420013243431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82571824305216 + 51770485719241 = 9086904^2 + 7195171^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134342310024457 is a prime.

It is not a weakly prime, because it can be changed into another prime (134342310024257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171155012228 + 67171155012229.

It is an arithmetic number, because the mean of its divisors is an integer number (67171155012229).

Almost surely, 2134342310024457 is an apocalyptic number.

It is an amenable number.

134342310024457 is a deficient number, since it is larger than the sum of its proper divisors (1).

134342310024457 is an equidigital number, since it uses as much as digits as its factorization.

134342310024457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 967680, while the sum is 43.

Adding to 134342310024457 its reverse (754420013243431), we get a palindrome (888762323267888).

The spelling of 134342310024457 in words is "one hundred thirty-four trillion, three hundred forty-two billion, three hundred ten million, twenty-four thousand, four hundred fifty-seven".