Base | Representation |
---|---|
bin | 1100001101111111001010… |
… | …0000000010110111100011 |
3 | 1202120022121121111011101211 |
4 | 3003133302200002313203 |
5 | 3230102203343034334 |
6 | 44323405325210551 |
7 | 2554414505142511 |
oct | 303376240026743 |
9 | 52508547434354 |
10 | 13434431221219 |
11 | 430a56820a218 |
12 | 160b823a00a57 |
13 | 765b27733628 |
14 | 346330d574b1 |
15 | 1846d8c0da64 |
hex | c37f2802de3 |
13434431221219 has 2 divisors, whose sum is σ = 13434431221220. Its totient is φ = 13434431221218.
The previous prime is 13434431221199. The next prime is 13434431221229. The reversal of 13434431221219 is 91212213443431.
13434431221219 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13434431221219 - 211 = 13434431219171 is a prime.
It is a super-2 number, since 2×134344312212192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13434431221229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717215610609 + 6717215610610.
It is an arithmetic number, because the mean of its divisors is an integer number (6717215610610).
Almost surely, 213434431221219 is an apocalyptic number.
13434431221219 is a deficient number, since it is larger than the sum of its proper divisors (1).
13434431221219 is an equidigital number, since it uses as much as digits as its factorization.
13434431221219 is an evil number, because the sum of its binary digits is even.
The product of its digits is 124416, while the sum is 40.
The spelling of 13434431221219 in words is "thirteen trillion, four hundred thirty-four billion, four hundred thirty-one million, two hundred twenty-one thousand, two hundred nineteen".
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