Base | Representation |
---|---|
bin | 1100001110000001010111… |
… | …1010110111001111011001 |
3 | 1202120101011000122022120212 |
4 | 3003200111322313033121 |
5 | 3230104413004012131 |
6 | 44323544313500505 |
7 | 2554435312061642 |
oct | 303402572671731 |
9 | 52511130568525 |
10 | 13435025454041 |
11 | 430a842689124 |
12 | 160b96aa11735 |
13 | 765bc0890199 |
14 | 346389c3c6c9 |
15 | 184720e8ca2b |
hex | c3815eb73d9 |
13435025454041 has 2 divisors, whose sum is σ = 13435025454042. Its totient is φ = 13435025454040.
The previous prime is 13435025453933. The next prime is 13435025454047. The reversal of 13435025454041 is 14045452053431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12614182206025 + 820843248016 = 3551645^2 + 906004^2 .
It is a cyclic number.
It is not a de Polignac number, because 13435025454041 - 230 = 13433951712217 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13435025454041.
It is not a weakly prime, because it can be changed into another prime (13435025454047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6717512727020 + 6717512727021.
It is an arithmetic number, because the mean of its divisors is an integer number (6717512727021).
Almost surely, 213435025454041 is an apocalyptic number.
It is an amenable number.
13435025454041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13435025454041 is an equidigital number, since it uses as much as digits as its factorization.
13435025454041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576000, while the sum is 41.
The spelling of 13435025454041 in words is "thirteen trillion, four hundred thirty-five billion, twenty-five million, four hundred fifty-four thousand, forty-one".
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