Base | Representation |
---|---|
bin | 10011100011010001011… |
… | …110111000111111010011 |
3 | 11202102220220200201112012 |
4 | 103203101132320333103 |
5 | 134003034322112433 |
6 | 2505114333453135 |
7 | 166032165252341 |
oct | 23432136707723 |
9 | 4672826621465 |
10 | 1343544332243 |
11 | 478880827533 |
12 | 19847a3411ab |
13 | 999075689c9 |
14 | 49056774991 |
15 | 24e36b74848 |
hex | 138d17b8fd3 |
1343544332243 has 2 divisors, whose sum is σ = 1343544332244. Its totient is φ = 1343544332242.
The previous prime is 1343544332189. The next prime is 1343544332311. The reversal of 1343544332243 is 3422334453431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1343544332243 is a prime.
It is a super-2 number, since 2×13435443322432 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1343544332243.
It is not a weakly prime, because it can be changed into another prime (1343544332743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671772166121 + 671772166122.
It is an arithmetic number, because the mean of its divisors is an integer number (671772166122).
Almost surely, 21343544332243 is an apocalyptic number.
1343544332243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1343544332243 is an equidigital number, since it uses as much as digits as its factorization.
1343544332243 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1244160, while the sum is 41.
Adding to 1343544332243 its reverse (3422334453431), we get a palindrome (4765878785674).
The spelling of 1343544332243 in words is "one trillion, three hundred forty-three billion, five hundred forty-four million, three hundred thirty-two thousand, two hundred forty-three".
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