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13437026252161 = 49992687942839
BaseRepresentation
bin1100001110001000110100…
…1011010011010110000001
31202120120022110111101121221
43003202031023103112001
53230123012210032121
644324515025515041
72554536015426421
oct303421513232601
952516273441557
1013437026252161
11431067a020396
121610228aa2a81
1376614c2568b5
143464d9864481
151847db95bb41
hexc388d2d3581

13437026252161 has 4 divisors (see below), whose sum is σ = 13439714200000. Its totient is φ = 13434338304324.

The previous prime is 13437026252159. The next prime is 13437026252249. The reversal of 13437026252161 is 16125262073431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13437026252161 - 21 = 13437026252159 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13437026252131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1343966421 + ... + 1343976418.

It is an arithmetic number, because the mean of its divisors is an integer number (3359928550000).

Almost surely, 213437026252161 is an apocalyptic number.

It is an amenable number.

13437026252161 is a deficient number, since it is larger than the sum of its proper divisors (2687947839).

13437026252161 is an equidigital number, since it uses as much as digits as its factorization.

13437026252161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2687947838.

The product of its (nonzero) digits is 362880, while the sum is 43.

The spelling of 13437026252161 in words is "thirteen trillion, four hundred thirty-seven billion, twenty-six million, two hundred fifty-two thousand, one hundred sixty-one".

Divisors: 1 4999 2687942839 13437026252161