Base | Representation |
---|---|
bin | 111110100101011101… |
… | …1001000001001000011 |
3 | 110211220122012012122221 |
4 | 1331022323020021003 |
5 | 4200223124000003 |
6 | 141424251511511 |
7 | 12465403436104 |
oct | 1751273101103 |
9 | 424818165587 |
10 | 134401000003 |
11 | 51aa9951616 |
12 | 2206a758597 |
13 | c89b8c7a4a |
14 | 670dba43ab |
15 | 37693e87bd |
hex | 1f4aec8243 |
134401000003 has 2 divisors, whose sum is σ = 134401000004. Its totient is φ = 134401000002.
The previous prime is 134400999959. The next prime is 134401000007. The reversal of 134401000003 is 300000104431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134401000003 is a prime.
It is not a weakly prime, because it can be changed into another prime (134401000007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200500001 + 67200500002.
It is an arithmetic number, because the mean of its divisors is an integer number (67200500002).
Almost surely, 2134401000003 is an apocalyptic number.
134401000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
134401000003 is an equidigital number, since it uses as much as digits as its factorization.
134401000003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 134401000003 its reverse (300000104431), we get a palindrome (434401104434).
The spelling of 134401000003 in words is "one hundred thirty-four billion, four hundred one million, three", and thus it is an aban number.
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