Base | Representation |
---|---|
bin | 10011100011101101001… |
… | …111101011100011100011 |
3 | 11202111010101010112112002 |
4 | 103203231033223203203 |
5 | 134010013041411412 |
6 | 2505232452554215 |
7 | 166046552262503 |
oct | 23435517534343 |
9 | 4674111115462 |
10 | 1344010107107 |
11 | 478a9a738038 |
12 | 19858a32296b |
13 | 9997cbc9935 |
14 | 4909c57ba03 |
15 | 24e629cbdc2 |
hex | 138ed3eb8e3 |
1344010107107 has 2 divisors, whose sum is σ = 1344010107108. Its totient is φ = 1344010107106.
The previous prime is 1344010107091. The next prime is 1344010107113. The reversal of 1344010107107 is 7017010104431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1344010107107 - 24 = 1344010107091 is a prime.
It is a super-2 number, since 2×13440101071072 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1344010107107.
It is not a weakly prime, because it can be changed into another prime (1344010107137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005053553 + 672005053554.
It is an arithmetic number, because the mean of its divisors is an integer number (672005053554).
Almost surely, 21344010107107 is an apocalyptic number.
1344010107107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344010107107 is an equidigital number, since it uses as much as digits as its factorization.
1344010107107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2352, while the sum is 29.
The spelling of 1344010107107 in words is "one trillion, three hundred forty-four billion, ten million, one hundred seven thousand, one hundred seven".
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