Base | Representation |
---|---|
bin | 10011100011101101010… |
… | …011111101101101001011 |
3 | 11202111010110020120212201 |
4 | 103203231103331231023 |
5 | 134010013333330102 |
6 | 2505232533021031 |
7 | 166046564650354 |
oct | 23435523755513 |
9 | 4674113216781 |
10 | 1344011230027 |
11 | 478aa0334774 |
12 | 19858a784777 |
13 | 99980200a9b |
14 | 4909c790d2b |
15 | 24e62b4e987 |
hex | 138ed4fdb4b |
1344011230027 has 2 divisors, whose sum is σ = 1344011230028. Its totient is φ = 1344011230026.
The previous prime is 1344011229973. The next prime is 1344011230103. The reversal of 1344011230027 is 7200321104431.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1344011230027 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1344011229977 and 1344011230004.
It is not a weakly prime, because it can be changed into another prime (1344011230427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672005615013 + 672005615014.
It is an arithmetic number, because the mean of its divisors is an integer number (672005615014).
Almost surely, 21344011230027 is an apocalyptic number.
1344011230027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344011230027 is an equidigital number, since it uses as much as digits as its factorization.
1344011230027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 1344011230027 its reverse (7200321104431), we get a palindrome (8544332334458).
The spelling of 1344011230027 in words is "one trillion, three hundred forty-four billion, eleven million, two hundred thirty thousand, twenty-seven".
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