Base | Representation |
---|---|
bin | 10011100011101101010… |
… | …100010010010010010010 |
3 | 11202111010110101212111202 |
4 | 103203231110102102102 |
5 | 134010013344024242 |
6 | 2505232534511202 |
7 | 166046565451205 |
oct | 23435524222222 |
9 | 4674113355452 |
10 | 1344011314322 |
11 | 478aa0392036 |
12 | 19858a805502 |
13 | 99980230271 |
14 | 4909c7b393c |
15 | 24e62b69932 |
hex | 138ed512492 |
1344011314322 has 4 divisors (see below), whose sum is σ = 2016016971486. Its totient is φ = 672005657160.
The previous prime is 1344011314301. The next prime is 1344011314339. The reversal of 1344011314322 is 2234131104431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1343561492641 + 449821681 = 1159121^2 + 21209^2 .
It is a super-3 number, since 3×13440113143223 (a number of 37 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336002828579 + ... + 336002828582.
Almost surely, 21344011314322 is an apocalyptic number.
1344011314322 is a deficient number, since it is larger than the sum of its proper divisors (672005657164).
1344011314322 is an equidigital number, since it uses as much as digits as its factorization.
1344011314322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 672005657163.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1344011314322 its reverse (2234131104431), we get a palindrome (3578142418753).
The spelling of 1344011314322 in words is "one trillion, three hundred forty-four billion, eleven million, three hundred fourteen thousand, three hundred twenty-two".
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