134401202224027 has 2 divisors, whose sum is σ = 134401202224028. Its totient is φ = 134401202224026.

The previous prime is 134401202223991. The next prime is 134401202224033. The reversal of 134401202224027 is 720422202104431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134401202224027 is a prime.

It is a super-3 number, since 3×134401202224027³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 134401202223983 and 134401202224001.

It is not a weakly prime, because it can be changed into another prime (134401202224327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200601112013 + 67200601112014.

It is an arithmetic number, because the mean of its divisors is an integer number (67200601112014).

Almost surely, 2^{134401202224027} is an apocalyptic number.

134401202224027 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401202224027 is an equidigital number, since it uses as much as digits as its factorization.

134401202224027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43008, while the sum is 34.

Adding to 134401202224027 its reverse (720422202104431), we get a palindrome (854823404328458).

The spelling of 134401202224027 in words is "one hundred thirty-four trillion, four hundred one billion, two hundred two million, two hundred twenty-four thousand, twenty-seven".