Base | Representation |
---|---|
bin | 11001000010001100… |
… | …00001000111100001 |
3 | 1021200122222012211102 |
4 | 30201012001013201 |
5 | 210011133034312 |
6 | 10101352324145 |
7 | 654026125031 |
oct | 144106010741 |
9 | 37618865742 |
10 | 13440127457 |
11 | 5777668759 |
12 | 27310a3655 |
13 | 1362622b53 |
14 | 916db78c1 |
15 | 539ddeec2 |
hex | 3211811e1 |
13440127457 has 2 divisors, whose sum is σ = 13440127458. Its totient is φ = 13440127456.
The previous prime is 13440127433. The next prime is 13440127507. The reversal of 13440127457 is 75472104431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11755763776 + 1684363681 = 108424^2 + 41041^2 .
It is an emirp because it is prime and its reverse (75472104431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13440127457 - 28 = 13440127201 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13440127457.
It is not a weakly prime, because it can be changed into another prime (13440127417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6720063728 + 6720063729.
It is an arithmetic number, because the mean of its divisors is an integer number (6720063729).
Almost surely, 213440127457 is an apocalyptic number.
It is an amenable number.
13440127457 is a deficient number, since it is larger than the sum of its proper divisors (1).
13440127457 is an equidigital number, since it uses as much as digits as its factorization.
13440127457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 94080, while the sum is 38.
The spelling of 13440127457 in words is "thirteen billion, four hundred forty million, one hundred twenty-seven thousand, four hundred fifty-seven".
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