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134401281593 is a prime number
BaseRepresentation
bin111110100101011110…
…0001100111000111001
3110211220122201111221012
41331022330030320321
54200223212002333
6141424301523305
712465406021055
oct1751274147071
9424818644835
10134401281593
1151aaa024137
122206a873535
13c89b995c77
14670dc38c65
153769451e48
hex1f4af0ce39

134401281593 has 2 divisors, whose sum is σ = 134401281594. Its totient is φ = 134401281592.

The previous prime is 134401281589. The next prime is 134401281653. The reversal of 134401281593 is 395182104431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131850324544 + 2550957049 = 363112^2 + 50507^2 .

It is a cyclic number.

It is not a de Polignac number, because 134401281593 - 22 = 134401281589 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134401281593.

It is not a weakly prime, because it can be changed into another prime (134401281583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67200640796 + 67200640797.

It is an arithmetic number, because the mean of its divisors is an integer number (67200640797).

Almost surely, 2134401281593 is an apocalyptic number.

It is an amenable number.

134401281593 is a deficient number, since it is larger than the sum of its proper divisors (1).

134401281593 is an equidigital number, since it uses as much as digits as its factorization.

134401281593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 41.

The spelling of 134401281593 in words is "one hundred thirty-four billion, four hundred one million, two hundred eighty-one thousand, five hundred ninety-three".